Solve 2x^2 - 4x - 6 = 0 using the quadratic formula.

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $24.99Unlock all

Prepare for the AMSOC 26-003 Module A Test. Utilize flashcards and multiple choice questions with hints and explanations. Ace your exam!

Multiple Choice

Solve 2x^2 - 4x - 6 = 0 using the quadratic formula.

Explanation:
Using the quadratic formula to solve quadratic equations is the go-to method when the equation is in the form ax^2 + bx + c = 0. The formula gives x = [-b ± sqrt(b^2 - 4ac)]/(2a). For 2x^2 - 4x - 6 = 0, identify a = 2, b = -4, c = -6. Compute the discriminant: b^2 - 4ac = (-4)^2 - 4*(2)*(-6) = 16 + 48 = 64, whose square root is 8. Then x = [-(-4) ± 8] / (2*2) = (4 ± 8) / 4. This yields x = (4 + 8)/4 = 12/4 = 3 and x = (4 - 8)/4 = -4/4 = -1. So the roots are x = 3 and x = -1.

Using the quadratic formula to solve quadratic equations is the go-to method when the equation is in the form ax^2 + bx + c = 0. The formula gives x = [-b ± sqrt(b^2 - 4ac)]/(2a).

For 2x^2 - 4x - 6 = 0, identify a = 2, b = -4, c = -6. Compute the discriminant: b^2 - 4ac = (-4)^2 - 4*(2)*(-6) = 16 + 48 = 64, whose square root is 8. Then

x = [-(-4) ± 8] / (2*2) = (4 ± 8) / 4.

This yields x = (4 + 8)/4 = 12/4 = 3 and x = (4 - 8)/4 = -4/4 = -1. So the roots are x = 3 and x = -1.

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy